Question

35. A vertical tower PQ subtends equal angle of 30° at each of the two places A and B, 60 meter apart on the ground. If AB subtends an angle of 60° at P(the foot of the tower) then the height of the tower is?? ​

Answer 1

Answer:

Step-by-step explanation:

Let PQ =h and PB =x =PA

then tan 30∘=hx⇒13–√=hx

⇒x=3–√h

using sine rule in ΔPAB

PA/(sin30∘)=AB/(sin60°)

⇒x=60/(sin30∘sin60°)

⇒√3h=60×½×x×(2/√3)

⇒h=20m