Question

35. An inclined track ends in a circular loop of
diameter 'D'. From what height on the track a
particle should be released so that it completes
that loop in the vertical plane ?
​

Answer 1

Answer:

5D/4

Explanation:

Given below

Answer 2

Answer:

For looping the loop, `v=sqrt(5gr)`

By law of conservation of enegy.

Loss in potential energy =Gain in kinetic energy

`rArr" " mgh-(1)/(2)mv^(2)`

`rArr" " h=(5r)/(2)`