Question

35. An object starts from rest and is acted upon by a
variable force F as shown in figure. If F, is the
initial value of the force, then the position of the
object, where it again comes to rest will be
FA
F.
OL
0
Х
(1)
2F
tana
(2)
F.
sina
(3)
2F
cota
(4)
F
2 cosa​

Answer 1

Answer:

Explanation:tanx=f°/X

X=f°/tanx

Final &initial K.E =0

Work=O

Area should be 0

Therefore the X should be equal in both negative and positive work done graph...x°(total)= 2f/tanx

Explanation: