Question

35. Answer the following: (a) Take Sarita’s present age to be y years

(i) What will be her age 5 years from now?

(ii) What was her age 3 years back?

(iii) Sarita’s grandfather is 6 times her age. What is the age of her grandfather?

(iv) Grandmother is 2 years younger than grandfather. What is grandmother's age?​

Answer 1

Step-by-step explanation:

Given Sarita’s present age to be y years

i) Her age 5 years from now = her present age + 5 = y + 5 years.

ii) Her age 3 years back = her present age – 3 years = y – 3 years

iii) Sarita’s grandfather age = 6 times her age = 6y years

iv) Grandmother’s age = Grandfather’s age – 2 = 6y – 2 years

v) Sarita’s father’s age is 5 years more than 3 times Sarita’s age = 5 + 3y

b) breadth of the rectangular hall = b meters

length of the hall = 4 meters less than 3 times the breadth = 3b – 4 meters

c) height of the rectangular box = h cm

length = 5 times the height = 5h cm

breadth = 10 cm less than the length = 5h – 10 cm

d) Step at which Meena is = s

Step at which Beena is = Meena’s step + 8 steps = s + 8

Step at which Leena is = Meena’s step – 7 = s – 7

Total number of steps = 4s – 10

e) Distance travelled by the bus in 1 hour = v km

Distance travelled in 5 hours = 5v km

So, total distance from Daspur to Beespur = Distance travelled in 5 hours + 20 = 5v + 20 km

Answer 2

Step-by-step explanation:

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