35. Calculate the force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another. (Gravitational constant, G = 6.7 x 10-11 Nm kg) *. What is the force of gravity on a body of mass 150 kg lying on the surface of the earth (Mass of earth = 6 x 104 kg; Radius of earth = 6.4 x 10 m; G = 67 * 10-11 Nm /kg)
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Answers
Answer:
The force of gravitation between two objects of masses 50 kg and 120 kg respectively kept at a distance of 10 m from one another is 400.2 × 10⁻¹¹ N.
The force of gravity on a body of mass 150 kg lying on the surface of the earth is 1465.5 N.
Explanation:
1) Two objects of masses 50 Kg and 120 Kg.
∴ M = 120 Kg
m = 50 Kg
Distance of separation, d = 10 m
Force of gravitation, F = G Mm / d²
= (6.67 × 10⁻¹¹ × 120 × 50) / (10²)
= 400.2 × 10⁻¹¹ N
2) Mass of the body, m = 150 Kg
Mass of the earth, M = 6 × 10²⁴ Kg
Distance of separation will be equal to the radius of the earth since the body is lying on the surface of the earth.
∴ d = Radius of the earth, R = 6.4 × 10⁶ m
Force of gravitation, F = G Mm / d²
= (6.67 × 10⁻¹¹ × 6 × 10²⁴ × 150) / (6.4 × 10⁶)²
= 1465.5 N