Question

35/ Eight times ofa number reduced by 10 is equal to the sum of six times the numbe and 4. Find number.​

Answer 1

$\huge \mathfrak \pink{Answer:}$

Let the number be $x$.

Eight times of the number reduced by 10 = 8$x$ – 10.

Sum of six times the number and 4 = 6$x$ + 4.

According to the given condition,

8$x$ – 10 = 6$x$ + 4

⇒ 8$x$ – 6$x$ = 4 + 10 (Transposing 6$x$ to LHS and 10 to RHS)

2$x$ = 14

⇒ $x$ = $\frac{14}{2}$(Transposing 2 to RHS)

$x$ = 7

∴ The required number is 7

Answer 2

Answer:

Let the number be x

=> 8x-10 = 6x+4

=> 8x-6x = 10+4

=> 2x = 14

=> x = 14/2

=> x = 7

Step-by-step explanation:

Hope this helps you and pls mark me as brainliest.