Question

35. Four cells 1.5 volts each are connected in series and used as a power source in a circuit.
(a) What is the potential difference at the terminals of this power source ?
(b) How many joules of electrical energy does 1 coulomb charge gain upon passing through (i) two cells, (ii)
three cells?​

Answer 1

Answer:

(a) 6V (b) (i) 3J (ii) 4.5J

Explanation:

when connected in series the voltages of all batteries add up

hence,voltage(potential difference) of power source=4×1.5=6V

work(energy)=voltage×charge

voltage across 2 cells=2×1.5=3V

energy=3×1=3J

voltage across 3 cells=3×1.5=4.5V

energy=4.5×1=4.5J

hope you find it helpful please mark brainliest