Question

35. If two bodies of mass 2kg and 4 kg have same momentum, ratio of
their kinetic energy is

​

Answer 1

Answer:

M1 = 2kg, M2 = 4 kg

Momentum = mv

According to the question,

M1 V1 = M2 V2

2 *v1 = 4* v2

v1/v2 = 2 /1

Kinetic energy, K. E. = 1/2 mv^2

K1/K2 = m1v1^2 / m2v2^2

K1/K2 = m1/m2 * ( v1/v2)^2

K1/K2 = ( 2/4) * (2/1) ^2

K1/K2 = 2/1

Ratio of their Kinetic Energy = 2 : 1

Answer 2

Answer:

2:1

Explanation:

KE=P²/2m

KE₁=P²/2×2  

     = P²/4

KE₂=P²/2×4  

     = P²/8

KE₁:KE₂ =  P²/4 :  P²/8

             =1 : 1/2

             =2:1

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