Question

(35. In the figure shown m, = 1 kg, m, = 2 kg, pulley is ideal Att = 0, both masses touches the ground and string
is taut. A force F = 2t is applied to pulley (t is in second) then m, is lifted off the ground at time (g = 10 m/s)
AF = 21
2
2 0​

Answer 1

Answer:

Time taken is 10 seconds.

Step-by-step explanation:

Since we know that the force is having the formulae of F=ma where m is the mass and a is the acceleration. This acceleration can be also written as velocity with respect to time or dv/dt. So, force F can be written as m(dv/dt) which will be equal to 2t (given in t he question).

So, now mdv=dt*2t.

Also, we can write mv=t^2 .

Since , by Newtons Laws of motion we have that:-

v=u+gt

Again u=0,

So, substituting the value of v in the force equation we get m*gt=t^2.

m=1, g=10

So, on solving we will get the time t=10 seconds.

Answer 2

Answer:

Step-by-step explanation:

Hope this answer is helpful