35. In the figure ZACE = 36°, 2CAE = 41°. Find x, y and z.
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since the sum of opposite angles of a cyclic quadrilateral is 180 deg.
therefore
x + 41 = 180
x = 180 - 41
x = 139
sum of the angles made on the one side of straight line is 180 deg
therefore
x + y =180
139 + y =180
y = 180-139
y = 41
now in the triangle CAE;
∠CEF is an external angle
therefore ∠CEF=∠ACE+∠CAE
external angle of a triangle is equal to the sum of two opposite angles
∠CEF=36+41=77
and in triangle DEF ;y+∠DEF+z=180
[sum of interior angles of a triangles]
z=180−(y+∠DEF)
z=180−(41+∠CEF)
z=180−(41+77)
z=180−118
z=62
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