Question

35.
In the given figure, PQR is an equilateral triangle and
QRST is a square. Then ZPSR =

(A)60°
(B)45°
(D) 15°
(C) 30°​

Answer 1

Answer:

15°

Step-by-step explanation:

Since PQRS is a square and ∆ SRT is an equilateral triangle .

:- PST = 90 ° and TSR = 60°

PSR + TSR = 90° + 60°

PST = 150°

Similarly , we have PST and QRT , we have

Thus , in triangles PST and QRT , we have

PS = QR

PST = QRT = 150°

and , ST = RT

So , by SAS congruence criterion , we have

∆ PST ≈ ∆ QRT PT = QT

2) In ∆ TQR , we have

QR = RT

TQR = QTR = x ( say )

Now ,

TQR + QTR + QRT = 180° 2x + 150° = 180° x = 15° .

i hope it's very easy for you t