Question

35. Let P be a set of squares, Q be set of parallelograms, R be a set of
quadrilaterals and S be a set of rectangles. Consider the following:
I. PcQ
II. RCP
III. PCS IV.SCR
Which of the above are correct?
(a) I, II and III (b) I, III and IV (c) I, II and IV (d) IIT and IV​

Answer 1

Given:

The$P$ be a set of squares $Q$be set of parallelograms and $S$ be a set of rectangles.

To find:

Which of the correct answer.

step-by-step explanation:

$P$≡set of square,

$Q$≡set of a parallelogram,

$R$≡set of quadrilaterals,

$S$≡set of rectangles,

All squares are parallelogram

$P$⊂$Q$

All are rectangles $P$⊂$s$ and are quadrilaterals $S$⊂$R$

Answer:

Therefore, the correct answer is $I,IIIand IV$.

Answer 2

Correct option is  (b) I, III and IV  means P ⊂  Q , P ⊂  S  and  S ⊂ R  are correct where P is a set of squares, Q is set of parallelograms, R is a set of

quadrilaterals and S is a set of rectangles.

Given:

P set of Squares

Q set of Parallelograms

R set of Quadrilaterals

S Set of Rectangles

Solution:

Squares , Parallelograms and Rectangles , all are type of Quadrilaterals

Hence subsets of Quadrilaterals

P , Q , S ⊂ R

Hence S ⊂ R  is correct

option iv is correct

All squares are rectangles , Parallelogram and Quadrilaterals

Hence Squares are subsets of all these

P ⊂  S , Q , R

Hence P ⊂  Q and P ⊂  S  is correct

options i) and iii) is correct

As P ⊂  R  so

R ⊂ P  is not correct

for example a trapezium is Quadrilateral but not a Square

Hence trapezium ∈ R   but not to P  hence R can not be sub set of P

Hence option ii) is not correct

Combining all correct option is  (b) I, III and IV

Additional Info

All Squares are rectangles , All rectangles are parallelogram and all parallelograms are quadrilaterals

Hence  P ⊂ S ⊂  Q ⊂ R

Learn More:

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