Question

35 men can make 70 toys in 8 days by working 8 hours a day. How many days will 56 men need to make 84 toys by working 12 hours every day?
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Answer 1

Answer:

4 days

Step-by-step explanation:

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35 men can make 70 toys in 8 days by working 8 hours a day. How many days will 56 men need to make 84 toys by working 12 hours every day?

Given:

1st Case:

• Men(1)= 35 men
• Days(1) = 8 days
• Hours(1)= 8 hours
• Number of toys=70

Let men, days and hours be $M_1,\:D_1\:and\:H_1$ respectively.....

2nd Case:

• Men(2)= 56 men
• Hours(2)= 12 hours
• Number of toys= 84

Let Men and hours be $M_2\:and\:H_2$ respectively.

Let the days of the second case be $D_2$

To find:

• $D_2$

Solution:

$\displaystyle\frac{ M_1 \times D_1 \times H_1 }{number \: of \: toys } = \displaystyle\frac{M_2 \times D_2 \times H_2}{number \: of \: toys}$

$\displaystyle\frac{35 \times 8 \times 8}{70} = \displaystyle\frac{56 \times D_2 \times 12}{84}$

$\displaystyle\frac{64}{2} = 8D_2 \:$

$16D_2=64 \:$

$D_2= \displaystyle\frac{64}{16} \:$

$D_2= 4days$

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Answer 2

Given:

1st Case:

Men(1)= 35 men

Days(1) = 8 days

Hours(1)= 8 hours

Number of toys=70

Let men, days and hours be M_1,\:D_1\:and\:H_1M

1

,D

1

andH

1

respectively.....

2nd Case:

Men(2)= 56 men

Hours(2)= 12 hours

Number of toys= 84

Let Men and hours be M_2\:and\:H_2M

2

andH

2

respectively.

Let the days of the second case be D_2D

2

To find:

D_2D

2

Solution:

\displaystyle\frac{ M_1 \times D_1 \times H_1 }{number \: of \: toys } = \displaystyle\frac{M_2 \times D_2 \times H_2}{number \: of \: toys}

numberoftoys

M

1

×D

1

×H

1

=

numberoftoys

M

2

×D

2

×H

2

\displaystyle\frac{35 \times 8 \times 8}{70} = \displaystyle\frac{56 \times D_2 \times 12}{84}

70

35×8×8

=

84

56×D

2

×12

\displaystyle\frac{64}{2} = 8D_2 \:

2

64

=8D

2

16D_2=64 \:16D

2

=64

D_2= \displaystyle\frac{64}{16} \:D

2

=

16

64

D_2= 4daysD

2

=4days