Question

35 ml oxygen gas were collected at 5°C ans and 758 mm pressure. calculate it's volume at NTP

Answer 1

I think this can help you

Answer 2

The volume is 0.037 L

Given:

Volume of $O_2$ gas = 35 mL = 0.035 L  

Temperature of $O_2$ gas = 5°C = 5 + 273 = 278 K  

Pressure of $O_2$ gas = 758 mm Hg = 0.997 atm

At NTP:

Temperature of $O_2$ gas = 298 K  

Pressure of $O_2$ gas = 1 atm  

Volume = ?

Solution:

On using, gas law, we get,

$\frac{P 1 V 1}{T 1} = \frac{P 2 V 2}{T 2}$

On substituting the value, we get,

$\frac{0.997 \times 0.035}{278}=\frac{1 \times V 2}{298}$

$\Rightarrow 0.0001255=\frac{V 2}{298}$

$\therefore V 2=0.037 \ L$