Question

35 ml pf oxygen were collected at 6°c and 758 mm pressure.cal. the volume at NTP?​

Answer 1

$\huge{\underline{\underline{\mathbf{Answer: -}}}}$

✡ given condition-

V1= 35ml

P1= 758mm

T1= 6+273= 279k

✡ final condition-

V2= ?

P2= 760mm

T2= 0+273= 273k

by applying gas equation, we have

$= > \frac{760 \times v_{2}}{273}$

$= > \frac{785 \times 35}{279}$

$\boxed{34.16\:ml}$

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Answer 2

Given conditions

$V_{ 1 }$ = 35 mL

$p_{ 1 }$ = 758 mm

$T_{ 1 }$= 6 + 273 = 279 K

Final conditions

$V_{ 2 }$ = ?mL

$p_{ 2}$ = 760 mm

$T_{ 2 }$ = 0+273 = 273 K

By applying gas equation, we have

760 x $V_{ 2 }$/273 = 758 x 35 /279

$V_{ 2 }$ = 758 x 35 x 273/279 x 760=34.16 mL

Volume of chloride gas = 34.16 mL