Question

35 ml sample of hydrogen peroxide gives off 500ml of o2 at 27°c and 1atm pressure. volume strength of h2o2 sample wii b

Answer 1

Use the formula PV=nRT and solve for n = PV/RT in order to get the number of moles of O2 given off. Substitute n=PV/RT Substitute

P= 1 atm, V=.500 L, R=0.082 L atm/ (mol K), T= 300 K

On solving n, you will get moles of O2 released. n=.0203 Volume of O2 relesed at stp from 22.4 L/moles of O2 at STP = 0.4553

For every mole of H2O2 you get one mole of O2 released, thus,

moles H2O2 in the solution = 00203 = 15.48 g H2O2 in the solution

On assuming the density of H2O2 is same as water, then you have 15.5 mL of H2O2 in the solution and the V/V % is 15.5x100/35 = 44%