Question

35. Prove that 3- 2 is a irrational number.​

Answer 1

Answer:

3-√2 = a/b ,where a and b are integers and b is not equal to zero .. therefore, √2 = (3b - a)/b is rational as a, b and 3 are integers.. But this contradicts the fact that √2 is irrational.. So, it concludes that 3-√2 is irrational.

Answer 2

Step-by-step explanation:

so it is a irrational

it should be done on squaring on both sides

than it will be proved