Question

35. Show that vectors A = 2î -- 3j- k and B =-6î +9j +3k
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Answer 1

Answer:

hence they are parallel

for further information refer to the attachment ☺☺☺

Answer 2

Explanation:

Given,

A = 2i - 3j - k

B = -6j + 9j + 3k

Two vectors are said to be parallel if we can write a relationship between them as

$\vec{A}=\lambda\vec{B}\;\;\;\textbf{or}\;\;\;\vec{B}=\lambda\vec{A}$

where λ is some constant.

Re-writing vector B as

$\vec{B}=-6\hat{i}+9\hat{j}+3\hat{k}\\\;\\\text{Taking (-3) common,}\\\;\\\vect{B}=-3(2\hat{i}-3\hat{j}-\hat{k})\\\;\\\vec{B}=-3(\vec{A})\\\;\\\vec{B}=-3\vec{A}$

Note:- Two vectors  are also said to be parallel if there cross prodcut is null vector.

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