Question

35. The velocity-üme graph of a body moving in a straight line is shown in the figure. The displacement and distance travelled by the body in 6 sec are respectively 51 V(m/s) - W NAHON WA i 2 3 4 5 6 1 2 31 (a) 8 m, 16 m (C) 16 m, 16 m t(sec) -> (b) 16 m, 8 m (d) 8 m, 8 m​

Answer 1

To find distance travelled, calculate area of v-t graph, which is equal to are a under graph:-

$\implies\sf{S = (4×2)+(2×2)+(2×2) = 16m}$

For displacement, calculate area under graph with positive velocity and subtract area enclosed with negative velocity.

$\sf{Displacement:- (8+4)-(2×2)= 12-4= 8m}$

$\sf\fbox{Ans:-\green{ 16m, 8m}}$

Answer 2

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$\large \fbox{Hv a look at d abve attchmnt}$

✓ So, the answer of the above question is 8m, 16m.