Question

35) The width of Radha's garden is
2/3 of its length. If the perimeter is 40m. Find its dimensions..​

Answer 1

Answer:

I have to send physics test and then I will be there at like midnight and the Two Strings of the day he was a good day at work and I I have to send physics and I have no idea

Answer 2

Answer:

8m by 12m

Step-by-step explanation:

Define x:

Let the length be x.

The width is 2/3 x.

Find the perimeter in term of x:

Perimeter = 2(Length + Width)

Perimeter = 2(x + 2/3 x)

Perimeter = 2(5/3 x)

Perimeter = 10/3 x

Solve x:

Perimeter = 10/3 x

Perimeter = 40 m (Given in the question)

10/3 x = 40

x = 40 ÷ 10/3

x = 40 x 3/10

x = 12 m

Find the dimension:

length = x = 12 m

width = 2/3 x = 2/3 (12) = 8 m

Answer: 8 m by 12 m