Question

35. Two years ago the age of elder brother was thrice the age of younger

brother. Six years hence, the elder brother will be twice as old as the

younger brother. Find their present ages.​

Answer 1

Answer:

present age of elder brother is 26

and younger brother is 10

Step-by-step explanation:

let us consider present age of elder brother and younger brother as "x" and "y" respectively.

case 1:

before 2 years,

age of elder brother is x-2

age of younger brother is y-2

acc. to question,

• x-2=3(y-2)
• x=3y-6+2
• x=2y+6 .........eqn.1

case 2:

after 6 years

age of elder brother is x+6

age of younger brother is y+6

acc. to question

• x+6=2(y+6)
• x+6=2y+12
• x=2y+6 ............eqn.2

subtracting eqn.1 and eqn.2 ,

x=26

y=10