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Which would contain 9.03 x 102 oxygen atoms?
A
0.25 mol aluminium oxide
1.5 mol sulfur trioxide
B 0.75 mol sulfur dioxide
Answers
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2
Answer:
0.75 mol sulfur dioxide
Explanation:
1 mole of any substance contains 6.02 x 10^23 atoms. (Avogadro's number)
1 mole Al2O3 contains 3 moles of oxygen. Therefore 0.25 moles of it will contain 0.25 moles x 3 = 0.75 moles.
If you multiply that with Avogadro's number, you will get 4.515 x 10^23
Doing the same for 0.75mol sulphur dioxide, (SO2), we can see that 1 mol of this substance contains 2 moles of oxygen. Therefore 0.75 moles of the gas will contain 0.75 x 2 = 1.5 moles of oxygen.
If 1.5 moles is multiplied by 6.02 x 10^23, we get 9.03 x 10^23 atoms of oxygen. BINGO!
If you follow the same step for 1.5 moles Sulphur trioxide (SO3), you will get 2.709 x 10^24 atoms.
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