350 cm^3 of methane and 175cm^3 of an unknown gas A diffused in the same time under similar conditions the molecular mass of gas A is
Answers
Answered by
6
Rate of diffusion is directly proportional to
molecular mass
1
∴
Time
Volume
∝
M
1
⇒Volume∝
M
1
Unknown gas volume diffused
CH
4
Volume diffused
=
CH
4
gas weight
Unknown gas weight
⇒
175
350
=
16
Unknown gas weight
Hence, molecular mass is 64 g/mol.
Answered by
1
Answer: 64 gram per mole
Explanation:
rate of diffusion is ∝ 1 / √molecular mass
V / T ∝ 1 / √MM
so, V is proportional to 1/ √MM
CH4 volume diffused =√unknown gas weight
unknown gas volume diffused √CH4 gas weight
350 = √gas A weight
175 √ 16
MOLECULAR MASS IS 64 GRAMS PER MOLES
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