Question

350! number of zero
with methods ​

Answer 1

Answer:

Hence number of zeros will be 15.

5: Find the number of zeros in 350!

a) 84

b) 85

c) 86

d) 87

Ans: c

Solution:

Maximum power of 5 in 350!

= 70 + 14 + 2

= 86

$ \displaystyle \begin{array}{l}\left[ \frac{350}{5} \right]+\left[ \frac{350}{{{5}^{2}}} \right]+\left[ \frac{350}{{{5}^{3}}} \right]+\left[ \frac{350}{{{5}^{4}}} \right]+…..\\\begin{array}{*{35}{l}}

=\text{ }70\text{ }+\text{ }14\text{ }+\text{ }2 \\

=\text{ }86 \\

\end{array}\end{array}$

So the number of zeros in the end of the 350! are 86.