352 mL of chlorine under a pressure of 680 mm Hg are placed in a container under a pressure of 1210 mm Hg. The temperature remains constant at 296K. What is the volume of the containers in liters
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Given:
Pressure of chlorine, P1 = 680 mm Hg
Pressure of container, P2 = 1210 mm Hg
Volume of chlorine, V1 = 352 mL
temperature is constant.
To Find:
Volume of container, V2
Calculation:
- As temperature is constant, Boyle's law will be used here as follows:
P1V1 = P2V2
⇒ V2 = P1V1/P2
⇒ V2 = 680 × 352 / 1210
⇒ V2 = 197.82 mL
- So the volume of container is 197.82 mL.
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