Math, asked by alyancheema75, 9 months ago

356) An animal feed is prepared by mixing two products A and B. Products A contains 5 units of
vitamin C while product B contains 8 units of Vitamin. Each feed should not be more than 30 kg in
weight and should contain at least 180 units of vitamin C. The cost of products A and B are Rs. 3 per
kg and Rs. 6 per kg respectively. How much should products A and B be mixed such that the cost of
the feed be minimum?​

Answers

Answered by amitnrw
0

20 kg of  A & 10 kg of B to be mixed Such that Cost is minimum

Step-by-step explanation:

Products A contains 5 units of vitamin C

Products B contains 8 units of vitamin C

A + B  ≤ 30

5A + 8B ≥  180

Cost  = 3A  + 6B

A             B        Vitamin   Cost

0             30         240       180

5             25         225       165

10            20         210        150

15            15          195        135

20           10          180        120

     

20 kg of  A & 10 kg of B to be mixed Such that Cost is minimum

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Attachments:
Answered by Fatimakincsem
0

The Cost will be minimum  if we mix 20 kg of A and 10 kg of B.

Step-by-step explanation:

Given data:

  • Products A = Contains 5 units of vitamin C
  • Products B  = Contains 8 units of vitamin C
  • Now the addition of A and B is less that or equal to 30 i.e.
  • A + B  ≤ 30
  • And addition of 5 A unit and 8 B unit is greater that or equal to 180 i.e.
  • 5 A + 8 B ≥  180

Chart for cost:

Cost  = 3 A  + 6 B

A         B        Vitamin   Cost

0        30         240       180

5         25         225       165

10        20         210        150

15        15          195        135

20       10          180        120      

The Cost will be minimum  if we mix 20 kg of A and 10 kg of B.

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