Question

35th answer please with workout​

Answer 1

Step-by-step explanation:

(g^2-2gh+h^2) can be written as (g-h)^2

and r^2s^2 can be written as (rs)^2

now

$( {g - h)}^{2} - {(rs)}^{2} is \: similar \: to \: {(a}^{2} - {b}^{2} )$

it can be factorised as (a-b)(a+b)

that is (g-h+rs)(g-h-rs)

therefore given expression can be factorised as (g-h-rs)(g-h+rs)