Question

35th one

pls fast. ......

Answer 1

Hi !

Solution :- from LHS

sinA /1 + cosA

multiplying by 1 - cosA in numerator and denominator .

or,, sinA(1-cosA)/1+cosA(1-cosA)

or, sinA (1-cosA)/(1-cos²A)

or, sinA(1-cosA)/sin²A {°•° 1-cos²A=sin²A}

or, (1-cosA)/sinA

or,1/sinA -cosA/sinA

cosecA - cotA

lHS =RHS Prooved ✔

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hope it helps you !!

@Raj❤