Question

√(36)²+(24)² plz solve in step wise​

Answer 1

Answer:

$\sqrt{ {36}^{2} } + \sqrt{ {24}^{2} } = 36 + 24 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: =6 0$

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Answer 2

The Solution of $\sqrt{(36)^{2}+(24)^{2} }$is$=12\sqrt{13}$

Step-by-step explanation:

Given:

The given value is $\sqrt{(36)^{2}+(24)^{2} }$.

To find:

Find the solution of $\sqrt{(36)^{2}+(24)^{2} }$

Solution:

$36^{2}+24^{2} =1872$

Find the prime factorization of $1872$

$=\sqrt{2^{4}.3^{2}.13 }$

$=\sqrt{2^{4} } \sqrt{3^{2} }\sqrt{13}$

we know that$\sqrt{2^{4} } =4$

$=4\sqrt{3^{2} }\sqrt{13}$

Now apply the radical rule $\sqrt{a^{2} } =a$

So, $\sqrt{3^{2} } =3$

$=4.3\sqrt{13}$

$=12\sqrt{13}$

Hence, the solution is $12\sqrt{13}$

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