36 (3x+5) +2(x +5) =35
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=>36(3x+5)+2(x+5)=35
Expanding the terms and removing the brackets:
=>108x+180+2x+10=35
=>110x+180+10=35
solving second term
=>110x+190=35
Arrange the terms and make constant terms together and Variable term on the other side:
=> when move 190 to right side its sign gets changed from +ve to -ve .
=>110x= 35-190
=>190 is being substracted from 35 but sign would be - ve as 190 is > than 35.
=>110x=-155
=>x= -155/110
=>x = -31/22
=>x= -1.40909 ( approx 1.41)
Check:
=>36[3(-1.41)+5)+2(-1.41+5)]=35
Solving the values inside the brackets
=>36(-4.23+5 ) +2(3.59)
=>36(0.77)+7.18
=>27.72+7.18
=>34.9 = 35 ( round off )
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