Question

36 - 41 का वर्ग अंतराल ज्ञात कीजिए ​

Answer 1

SOLUTION

TO DETERMINE

The class length of the class 36 - 41

CONCEPT TO BE IMPLEMENTED

CLASS INTERVAL

When the number of sample values are large in number and are in wide range, then the whole data is divided in a number of several groups according to the size of the sample. Each of these groups, made as above, is known as class interval

CLASS BOUNDARY

When class intervals are such a type that the upper class limit of any class is not equal to lower class limit of successive class then to get any continuous graphical representation of the data it is sometimes required to rearrange the class limits in such a way that the upper class limit of any class coincides with the lower class limit of next class. Then these class limits are called class boundaries. The lower and upper ends of any class are called lower and upper class boundaries respectively.

CLASS LENGTH

Length of the class interval of an class is defined to be the difference between the lower and upper class boundaries ( not class limits) of that particular class interval.

Class length = Upper Class boundary - Lower class boundary

EVALUATION

Here the given class interval 36 - 41

Upper Class boundary = 41

Lower class boundary = 36

Hence Class length

= Upper Class boundary - Lower class boundary

= 41 - 36

= 5

━━━━━━━━━━━━━━━━

Learn more from Brainly :-

$1.$ the data is such that is its maximum value is 222 and the range is 52 then the minimum value is

https://brainly.in/question/22317971

2. the standard deviation of a data is 2.8 ,if 5 is added to all the data values then the new standard deviation is

https://brainly.in/question/13716661