Question

36,42,16,20,36,42,4,??

Answer 1

Answer:

10

Mark as brainlist

Step-by-step explanation:

Hope it help you

Answer 2

The given series are:

36, 42, 16, 20, 36, 42, 4, ?

We have to find, the value of missing number (?) =

Solution:

The pattern follow(pair of numbers):

$x^{2} ,(x^{2}+x)$.

36, 42 = $6^{2},(6^{2}+6)$

= 36, (36 + 6)

= 36, 42

16, 20

16, 20 = $4^{2},(4^{2}+4)$

= 16, (16 + 4)

= 16, 20

36, 42 = $6^{2},(6^{2}+6)$

= 36, (36 + 6)

= 36, 42

Similarly,

4, ? = $2^{2},(2^{2}+2)$

= 4, (4 + 2)

= 4, 6

∴ Missing number (?) = 6

Thus, the value of missing number(?) is "equal to 6".