Question

36+48+60+..n. find the 10th terms of this series?​

Answer 1

Answer:

Here a=36 ,d=12 n=10

, then 10th term of AP is= a+9d

=36+9*12

=36+108

=144

Answer 2

Answer:

$a_{10}=144$

Step-by-step explanation:

$a=36, l=n,d=t_{2}-t_{1}=48-36=12 \\a_{n}=a+(n-1)d\\a_{10}=36+(10-1)12\\a_{10}=36+9*12\\a_{10}=36+108\\a_{10}=144$

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