Question

36.5 gram of HCl an dissolve in water 100 gram o water Find molality

Answer 1

Hey dear, please refer to the attachments for your answer.

Answer 2

$\checkmark$ Given:

36.5 gram of HCl an dissolve in water 100 gram of water

$\checkmark$ To Find:

Molality

$\checkmark$ Solution:

We know that,

$\red{\bigstar \ \boxed{\rm m=\dfrac{n}{w}}}$

Here,

• m = molality
• n = no. of moles
• w = mass of solvent (kg)

According to the Question,

We are asked to find the Molality

So, must find "m"

$\dagger$ Finding no. of moles:

We know that,

$\blue{\longrightarrow \rm n=\dfrac{m}{M}}$

Here,

• n = no. of moles
• m = given mass
• M = molecular mass

Given that,

36.5 gram of HCl an dissolve in water 100 gram of water

Hence,

• m = 36.5 g

We know that,

Molecular mass of HCl is 36.5 g

Hence,

• M = 36.5 g

By substituting the values,

We get,

$\green{\rm \implies n=\dfrac{36.5}{36.5}}$

Therefore,

$\orange{\rm \implies n=1 \ mole}$

Given that,

36.5 gram of HCl an dissolve in water 100 gram of water

Hence,

• w = 100 g = 0.1 kg

By substituting the values,

We get,

$\blue{\rm \implies m=\dfrac{1}{0.1}}$

Therefore,

$\pink{\rm \implies m=10 }$

Hence,

$\star$ Molality (m) = 10 m