Question

36,90,225 following questions are in continued proportion

Answer 1

Step-by-step explanation:

$\frac{36}{90} = \frac{18 \times2 }{18 \times 5} = \frac{2}{5} ....(1) \\ \\ \frac{90}{225} = \frac{45 \times2 }{45 \times 5} = \frac{2}{5} ....(2) \\ \\ from \: equations \: (1) \: \& \: (2) \\ \\ \frac{36}{90} = \frac{90}{225} \\ \\ \therefore \: 36, \: 90 \: \& \:225 \: are \: in \: continued \: \\ proportion.$