Question

36.) A 30N object is dragged along horizontal surface for a distance of
10m if the coefficient of fraction is 0.2 ...........what is minimum
amount of work that most be done​

Answer 1

Answer:

60 J

Explanation:

Normal Force on object (N) = Mg = 30 N

So, frictional force on object (f) =  uN = 0.2 * 30 = 6 N

So, Force required to drag the object = f = 6 N

Work = Force * Displacement

or W = 6 * 10 = 60 J