Question

36. A balloon is rising vertically up at constant speed
10 m/s. A stone is dropped from it when the
balloon is at a height of 40 m. Total distance
covered by the stone before reaching the ground is
(take g = 10 m/s2)
(1) 40 m
(2) 45 m
(3) 50 m
(4) 60 m
​

Answer 1

Answer:

50m

Explanation:

Refer to the material.

Answer 2

Answer:

The total distance covered by the stone before reaching the ground is 50 m.

(3) is correct option.

Explanation:

Given that,

Speed = 10 m/s

Height = 40 m

We need to calculate the distance

Using equation of motion

$v^2=u^2+2as$

Where, v = final velocity

u = initial velocity

g = acceleration due to gravity

Put the value in the equation

$0=10^2+2\times(-10)\times s'$

$s'=\dfrac{100}{20}$

$s'=5\ m$

Upward distance after drop = 5 m

The stone will cover similar distance downward to reach position where the stone was first drop.

The total distance is

$s'''=s+s'+s''$

Put the value in the formula

$s'''=40+5+5$

$s'''=50\ m$

Hence, The total distance covered by the stone before reaching the ground is 50 m.