36. A block of mass 4 kg is suspended with a mass ess thread. The maximum tension in the thread is 72 N then find the acceleration of the body.
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Answer:
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A mass of 1kg is suspended by a thread. It is first lifted up with an acceleration 4.9m/s
2
,and then lowered with an acceleration 4.9m/s
2
. What is the ratio of tension in the two cases?
Medium
Answer
Correct option is
A
3 : 1
Given,
a
1
=a
2
=4.9m/s
2
g=9.8m/s
2
m=1kg
Case (1):- From free body diagram,
T
1
−mg=ma
1
T
1
=m(a+g)
T
1
=1(4.9+9.8)
T
1
=17.47N
Case (2):- From free body diagram,
mg−T
2
=ma
2
T
2
=m(g−a)
T
2
=1(9.8−4.9)
T
2
=4.9N
Ratio,
T
2
T
1
=
1
3
T
1
:T
2
=3:1
Explanation:
Answer:
hi
Explanation:
the answer is in the attachment
