36. A body has mass 2 kg and is at rest. A
steady force of 4 N starts acting on it until
5 s. How far is the body from the initial
position at 1 = 8 s?
1) 25 m 2) 30 m 3)* 55 m
4) 80 m
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M =2kg
F=2N
u=?
v=0
t=5s
F=m×v-u/t
4=2× 0-u/5
4×5=-u
u=-20
F=2N
u=?
v=0
t=5s
F=m×v-u/t
4=2× 0-u/5
4×5=-u
u=-20
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