Question

36. A car of mass 1000 kg is moving on a straight road with
a velocity of 36 km/hr. It is stopped by a force of
friction at distance 50 m. Find : (i) value of force of
friction (ii) coefficient of friction between the tyre and
the road.
(g = 10 m/s2)​

Answer 1

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Answer:The brakes of a car moving at 20m/s along a horizontal road are suddenly applied and it comes to rest after travelling some distance. If the coefficient of friction between the tyres and the road is 0.90 and it is assumed that all four tyres behave identically, find the shortest distance the car would travel before coming to a stop