Math, asked by karthiksridatta269, 1 month ago

36. A solid metallic cylinder of diameter 12 cm and height 15 cm is melted and recast into 12 toys in the shape of a right circular cone mounted on a hemisphere of same radius. Find the radius of the hemisphere and total height of the toy, if the height of the cone is 3 times the radius.

Answers

Answered by palsabita1957
135

Answer :

The Number of toys formed is 12.

Step - by - step - explanation :

SOLUTION :

Given :  

Diameter of cylinder = 12 cm  

Radius of cylinder , R = 12/2 = 6 cm

Radius of hemisphere = Radius of the cone, r  = 3 cm

Height of the cylinder, H = 15 m

Height of the toy = 12 cm  

Height of cone, h = 12 - 3 = 9 cm

Volume of solid cylinder,V = πR²H

V = π× 6² × 15

V = π × 36 × 15

V of solid cylinder = 540π cm³

Volume of toy = Volume of hemisphere + Volume of cone

= (2/3πr³ + 1/3πr²h)

= ⅓ πr²(2r + h)

= ⅓ π × 3² (2 × 3 + 9)

= π/3 × 9 (6 + 9)

= 3π× 15  

= 45 π cm³

Volume of toy = 45 π cm³

Number of toys formed ,n = Volume of solid cylinder/Volume of toy

n = 540π/45π

n = 540/45

n = 12

Hence, the Number of toys formed is 12.

HOPE THIS ANSWER WILL HELP YOU….

Attachments:
Answered by ITzUnknown100
5

Answer:

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