Question

36. An electric lamp of resistance 20 ohm and a conductor of resistance 4 ohm are
connected to a 6V battery as shown in the circuit. Calculate


i) The total resistance of the circuit
ii) The current through the circuit
iii) Power of the lamp
iv) The potential difference across the conductor
​

Answer 1

Total resistance

=20+4=24ohm

as connected is SERIES

V=IR

I=V/R

I=6/24

I=1/4=0.25A

P=VI

P=6×0.25

P=1.5W

V=IR

V=0.25×20

V=5