36. Construct a AABC in which BC = 4.5 cm, 2B = 60° and AB + AC = 7 cm.
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Answer:
1. Construct a line segment BC of 4.5 cm
2. Construct a 45° angle at B
3. Take the length of PB as 5.6 cm
4. Join PC
5. Construct a bisector at PC . The line will meet BP at point A . Join AC
We get required triangle
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