36) Construct a triangle with sides 5cm, 6cm and 7 cm and then construct another triangle whose
sides are
3/5
of the corresponding sides of the given triangle
Answers
Answer:
Here your answer
Step-by-step explanation:
Constructing the first triangle:
Step 1: Draw base AB of length 7 cm
Step 2: Place a compass on A and draw an arc of radius 5 cm
Step 3: Place the compass on B and draw an arc of radius 6 cm such that it intersects the arc drawn in step 2.
Step 4: Mark the intersection of the two arcs as C and join A−C and B−C
△ABC is the given triangle.
Let △PAQ be the required triangle.
Step 1: Draw a ray AX from point A on the opposite side of C, making an acute angle with AB.
Step 2: Mark 7 equidistant points A
1
,A
2
,A
3
,...,A
7
on ray AX.
Step 3: Join A
5
to B.
Step 4: Draw A
7
Q parallel to A
5
B and mark the point on the extension of line AB as Q.
Step 5: Draw PQ parallel to BC and mark the intersection point on the extension of AC as P.
△PAQ is the required triangle.
Answer:
hey here is your construction in above pics
pls mark it as brainliest pls
