Question

36. (d) 33228 28. The LCM and the HCF of two numbers are 1001 and 7 respectively. How many such pairs are possible? (a) o (b) 1 (c) 2 (d) 7​

Answer 1

Answer:

d) 33228 28. The LCM and the HCF of two numbers are 1001 and 7 respectively. How many such pairs are

Answer 2

Answer:

LCM=1001 and HCF=7

Let the two numbers be x and y.

Therefore,

x=7a and y=7b, where a and b are co-primes.

We have,

x×y=LCM×HCF

7a×7b=1001×7

ab=143

(a,b)=(1,143) or (11,13)

There are two pairs of numbers.

Step-by-step explanation: