Question

36 g of glucose comolas mass - 180 gimol)​

Answer 1

Therefore, correct answer is option B i.e. 36g of glucose (molar mass = 180 g/mol) is present in 500g of water, the molality of the solution is 0.4m.

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Answer 2

Answer:

Therefore, correct answer is option B i.e. 36g of glucose (molar mass = 180 g/mol) is present in 500g of water, the molality of the solution is 0.4m.

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