Question

36] If x-tan2 60+3sin2 60-tan2 60° =6, find the value of 'x.​

Answer 1

Answer:

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x tan2 60°+ 3sin2 60°- 3/4 tan2 30°= 6

= x(1/√3)2 + 3 ( 2/√3)2- 3/4 (1/2)=6

= x/3+4-3/8=6

= x/3 + (32-3)/8 =6

= x/3 + 29/8 =6

= x/3 =6 - 29/8

= x/3 =48 -29/8

= x/3 =19/8

= x =57/8 ...

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