Math, asked by swani3577, 1 year ago

36 kg of gunpowder contains 27kg nitre,5.4kg charcol and rest sulphur.find the percentage content of sulphur in the gunpowder

Answers

Answered by santy2
11

Answer:

10%

Step-by-step explanation:

Total weight of gunpowder = 36 kg

CONTENTS OF THE GUNPOWDER;

1) Nitre = 27 kg

2) Charcol = 5.4 kg

3) Sulphur = ?? (rest)

To find the amount of sulphur(S) in the gunpowder;

(27+5.4+S)kg = 36 kg

(32.4+S)kg=36 kg

S = (36-32.4) kg

S = 3.6 kg

Finding the percentage content of sulphur in the gunpowder;

(Amount of sulphur / Total amount of gunpowder) * 100%

(3.6/36) * 100%

0.1 * 100%

Percentage content of Sulphur = 10%


Answered by avinashsingh48
6
Answer:

10%

Step-by-step explanation:

Total weight of gunpowder = 36 kg

CONTENTS OF THE GUNPOWDER;

1) Nitre = 27 kg

2) Charcol = 5.4 kg

3) Sulphur = ?? (rest)

To find the amount of sulphur(S) in the gunpowder;

(27+5.4+S)kg = 36 kg

(32.4+S)kg=36 kg

S = (36-32.4) kg

S = 3.6 kg

Finding the percentage content of sulphur in the gunpowder;

(Amount of sulphur / Total amount of gunpowder) * 100%

(3.6/36) * 100%

0.1 * 100%

Percentage content of Sulphur = 10%


Similar questions