Question

36% of tarts that the baker baked were strawberry tarts. He baked 98 more chocolate tarts than strawberry tarts. How many tarts did the baker baked in all ?

Answer 1

Answer:

Let the total tarts be x.

Strawberry tarts = 36%

= $\frac{36y}{100}$

Chocolate tarts = 98 more than strawberry tarts

= $\frac{36y}{100} + 98$

Total tarts = Chocolate tarts + Strawberry tarts

$= \frac{36y}{100} + \frac{36y}{100} + 98$

$= 2[\frac{36y}{100}] + 98$

$= \frac{72y}{100} + 98$

$=\frac{72y + 9800}{100}$

Hope it helps

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Answer 2

Answer:350

100%-36%=64%(chocolate tarts)

64%-36%=28%(difference)

28%→98

1%→98÷28%=3.5

100%→3.5×100=350