$36\%$ of the beans in Pythagoras's soup are lentils, and $33\frac13\%$ of those lentils are green. If Pythagoras removes all the green lentils from his soup, then $x\%$ of the original beans remains. What is $x$?
Answers
The value of x is 88%.
Step-by-step explanation:
It is given that,
The percentage of lentils in the soup = 36% = 0.36
The fraction of the lentils which are green = 33
∴ The amount of green beans in the soup will be
= 0.36 * 33
= 0.36 * 100/3
= 0.36 × 33.34
= 12
∴ The percentage of green beans = 12% ……. [considering that the percentage of soup be 100%]
Thus,
The percentage of the original beans in the soup is given by,
= 100 - 12
= 88% ← is the value of x since after removing all the green lentils, "x%" of the original beans is left
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